Question

Find the sum of the first 30 positive integers divisible by 6.

please give me full explanation answer​

Answer 1

the sum of first 30 positive integers which are divisible by 6 by applying arithmetic progression.

Address the formula, input parameters & values.

Input parameters & values:

The number series 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, . . . . , 180.

The first term a = 6

The common difference d = 6

Total number of terms n = 30

step 2 apply the input parameter values in the AP formula

Sum = n/2 x (a + Tn)

= 30/2 x (6 + 180)

= (30 x 186)/ 2

= 5580/2

6 + 12 + 18 + 24 + 30 + 36 + 42 + 48 + 54 + 60 + . . . . + 180 = 2790

Therefore, 2790 is the sum of first 30 positive integers which are divisible by 6.

# Capricorn answer

Answer 2

★᭄ꦿ᭄Answer★᭄ꦿ᭄

2790

☆ Explained

The numbers will be:

6,12,18, - t30

S= n/2[2a + (n-1)d]

= 15[12 + (29*6)]

= 15[6 + 6*30]

= 15*186

= 2790