Question

find the sum of the first 30 terms of an AP whose n term is given by a n =3-2n​

Answer 1

Answer:

Sum of first 30 terms of AP is 1020.

Answer 2

Answer:

$\huge{ \boxed{ \bold{ \mathtt{ \star{ \blue{ \green{ \red{ \pink{ \purple{ \orange{a}{n} }{s} }{w} }{e} }{r} }{} }{} }{} }{} }{} }{}$

$\sf{ \bold{ \underline{ \pink{from \: the \: question}{} }{} }{} }{}$

$\sf{ \bold{ \red{correct \: n \: = 2 - 3n}{} }{} }{}$

Given to find the 30 terms of an Ap

given n terms = 2-3n

So

a1 = -1

a30 = 2-3(30)= -88

Sum of 30 terms = 30/2 [(-1)-(-88)

=> (15)*(-89)