Math, asked by menakagowdaumeghanag, 6 days ago

find the sum of the first 30positive integers divisible by 6​

Answers

Answered by MANOBALAN2305
0

apply the input parameter values in the AP formula

Sum = n/2 x (a + Tn)

= 30/2 x (6 + 180)

= (30 x 186)/ 2

= 5580/2

6 + 12 + 18 + 24 + 30 + 36 + 42 + 48 + 54 + 60 + .  .  .  .   + 180 = 2790

Therefore, 2790 is the sum of first 30 positive integers which are divisible by 6.

Answered by Anonymous
3

Answer:

2790 is the sum of first 30 positive integers which are divisible by 6.

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