Question

Find the sum of the first 31 terms of an AP whose nth term is given by 3 + 2/3n ?
Please ans. fast it's urgent

Answer 1

It is given that nth term is given by 3+2/3n
So , an = 3+2/3n
a=3+2/3(1)
=3+2/3
a1=11/3
a2=3+2/3(2)
=3+4/3
=13/3
So , d=a2-a1=13/3-11/3
d=2/3

S31=n/2{2a+(n-1)d}
=31/2(2(11/3)+(30)(2/3)
=31/2(22/3+60/3)
=31/2(82/3)
=1271/3
=423.66
Hope this helps you.,!!!

Answer 2

Answer:

it may help you

Step-by-step explanation:

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