Question

Find the sum of the first 40 positive integers
divisible by 6.
​

Answer 1

Answer:

6,12,18...........

d=6

s40=n/2 (2a+n-1×d)

=40/2(2×6+n-1×6)

you put in this value and you get the answer I hope it will help you and pls follow me

Answer 2

Answer:

$\green{Solution}$

$\green{Sn = n/2(2a + [ n - 1 ]d}$

• n = 6
• d = 6
• a = 6

$\red{Sn = 6/2 ( 2×6 + [ 6 - 1)] 6)}$

$\green{= 3 ( 12 + 30)}$

$\green{= 3 × 42}$

$\green{= 126}$

$\huge{MaY hElP}$