Question

Find the sum of the first 40 positive integers divisible by 6 also find the sum of the first 20 positive integers divisible by 5 or 7

Answer 1

a= 6.

d= 6

$s_{n} = \frac{n}{2} |2a + |n - 1| d |$

=40÷2{12 + (40-1)6}

=20{12+234}

=246×20

=492

Answer 2

Step-by-step explanation:

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