find the sum of the first 50 natural numbers
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Answered by
82
a= 1
d = 1
n=50
Sn = n[2a +(n-1)d]/ 2
= 25 (2 + 49*1)
= 25 * 51
= 1275
d = 1
n=50
Sn = n[2a +(n-1)d]/ 2
= 25 (2 + 49*1)
= 25 * 51
= 1275
sathish22:
you are correct
Answered by
15
Answer:
Step-by-step explanation:
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