find the sum of the first 50 natural numbers
Answers
Answered by
6
Answer:
The sum of first n natural numbers is
S(n)=(
2
n
)(first+last)
S(50)=
2
50
(1+50)
S(50)=25×51
=1275
Answered by
4
Answer:
2450
Step-by-step explanation:
a=1,d=1,n=50
formula=n/2(a+(n-1)*d)
=50÷2(1+(50-1)*1)
=25*50
=1275
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