Question

find the sum of the first 50 positive integers divisible by 6?
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Answer 1

first positive integer divisible by 6=6

here, in this A. P

a=6

d=6 (common difference will be 6 because they are multiple of 6)

sum =n/2{2a+(n-1) d}

sum=50/2{2*6+(50-1)*6}

sum=25*(12+49*6)

sum=25*(12+294)

sum=25*306

sum=7650

Answer 2

Step-by-step explanation:

refer photo for answer

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