find the sum of the first 51 terms of an AP whose second and third terms are 14 and 18 respectively
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Here's , ur answer :-
=) A2 = 14 and a3 = 18
=) Common difference = a3 - a2 = 18 - 14 = 4 = d
Now ,
=) a2 = a+d=14
=) a+4=14
=) a = 10
Now, sum of 51 terms
={51(2a+(50)d)}/2
={51(20+200)}/2
={51×220}/2
=51×110=5610
Therefore , sum of 51 terms is 5610
________________________
HOPE , IT HELPS ... ✌️
______________________
______________________
Here's , ur answer :-
=) A2 = 14 and a3 = 18
=) Common difference = a3 - a2 = 18 - 14 = 4 = d
Now ,
=) a2 = a+d=14
=) a+4=14
=) a = 10
Now, sum of 51 terms
={51(2a+(50)d)}/2
={51(20+200)}/2
={51×220}/2
=51×110=5610
Therefore , sum of 51 terms is 5610
________________________
HOPE , IT HELPS ... ✌️
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