Math, asked by OSMBOY, 1 year ago

find the sum of the first 51 terms of an AP whose second and third terms are 14 and 18 respectively

Answers

Answered by Anonymous
25
HEY DEAR ... ✌️

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Here's , ur answer :-


=) A2 = 14 and a3 = 18


=) Common difference = a3 - a2 = 18 - 14 = 4 = d


Now ,

=) a2 = a+d=14


=) a+4=14


=) a = 10


Now, sum of 51 terms


={51(2a+(50)d)}/2


={51(20+200)}/2


={51×220}/2


=51×110=5610


Therefore , sum of 51 terms is 5610


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HOPE , IT HELPS ... ✌️


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Answered by Prashant7856
12

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