Find the sum of the first 8 multiples of 4
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the sum is 144. pls mark it brainliest,,,...
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First 8 multiples of 4 are
4,8,12......32
an=32
a=4 d=4 n=8
Sn=n/2[2a+(n-1)d]
S8=8/2|2x4+(8-1)4]
=4(8+28)
=4x36
=144
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