find the sum of the first 80 numbers
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Answered by
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sum of n natural numbers = n(n+ 1 )/ 2
sum of 80 natural numbers = 80× 81 /2
= 40 × 81 = 3240
sum of 80 natural numbers = 80× 81 /2
= 40 × 81 = 3240
Answered by
3
Dear user !!
Sum of n numbers ( consecutively starting ) is given by : n ( n+1 )/2
Here, n = 80
===> Sum = (80 X 81)/2
= 40 X 81
= 3240 >>>>Ans.
Hope it helps you !!
Sum of n numbers ( consecutively starting ) is given by : n ( n+1 )/2
Here, n = 80
===> Sum = (80 X 81)/2
= 40 X 81
= 3240 >>>>Ans.
Hope it helps you !!
Anonymous:
please mark it as brainliest answer
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