find the sum of the first hundred even natural numbers divisible by 5
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5,10,15,20...100 term
By solving Sn= n/2{2a+(n-1)d}
we get, Sn= 520
so sum of 1st 100 natural no.divisible by 5=520
By solving Sn= n/2{2a+(n-1)d}
we get, Sn= 520
so sum of 1st 100 natural no.divisible by 5=520
Answered by
1
:the final answer that we get is 50500
By using Sn formula we can get the required answer
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