Question

Find the sum of the first hundred even natural numbers divisible by 5.

Answer 1

The even natural numbers divisible by 5 are the multiples of 10
They are 10(1),10(2),10(3).....10(100)
=10(1+2+3+4+5+6.........+100)
By the formula
$n(n + 1) \div 2$
$10(100(100 + 1) \div 2)$
$10(100 \times 101 \div 2)$
$10(50 \times 101)$
$10 \times 5050$
The answer is 50500

Answer 2

here is ur answer mate plz mark it as brainlist