Find the sum of the first hundred even natural numbers divisible by 5.
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The numbers are even and are divisible by 5 .
So the numbers are divisible by 10.
It means the numbers are of the form...
10n where n is a natural Number
belongs from 1 to 100.
So summation of first 100
=£10n
=10£n
=10[n(n+1)/2]
=10[100(101)/2)]
=500×101
=50500
Here £ is for summation from 1 to 100
So the numbers are divisible by 10.
It means the numbers are of the form...
10n where n is a natural Number
belongs from 1 to 100.
So summation of first 100
=£10n
=10£n
=10[n(n+1)/2]
=10[100(101)/2)]
=500×101
=50500
Here £ is for summation from 1 to 100
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