find the sum of the first m terms of an ap whose nth term is (5-6n). hence also find the sum of its first 20 terms !! pls solve it quickly !! thank u !!
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Answered by
0
Given:
t(n)= 5 - 6n
Sum of the first 20 terms
= n/2 [a + l]
= 20/2 [ t(1) + t(20)]
= 10 [ (5-6) + (5-120)]
= 10 [ -1 -115]
= 10 × [ - 116] = - 1160
I hope this answer helps you
t(n)= 5 - 6n
Sum of the first 20 terms
= n/2 [a + l]
= 20/2 [ t(1) + t(20)]
= 10 [ (5-6) + (5-120)]
= 10 [ -1 -115]
= 10 × [ - 116] = - 1160
I hope this answer helps you
Answered by
1
The sum of the first 20 terms of the given AP is -1160.
The general term = 5 - 6n
First term = 5 - 6(1) = -1
mth term = 5 - 6(m)
Sum (S) = m/2 (first term + mth term)
= m/2 (4 - 6m)
Putting m = 20, S = 10 x (-116)
= -1160
The general term = 5 - 6n
First term = 5 - 6(1) = -1
mth term = 5 - 6(m)
Sum (S) = m/2 (first term + mth term)
= m/2 (4 - 6m)
Putting m = 20, S = 10 x (-116)
= -1160
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