find the sum of the first n odd natural numbers
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Answered by
18
Let The AP is 1,3,5,7......
a =1; d =2
Sn = n/2[2a+(n-1)d]
= n/2[2+2n-2]
= n2
a =1; d =2
Sn = n/2[2a+(n-1)d]
= n/2[2+2n-2]
= n2
sanjeevkush:
done
noooo
I didn't
what's the matter?
sorry for that comment
i apologize my mistake
plz forgive me
okk
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Answered by
17
here's ur answer if like please thank my answer .
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this is wrong upper one is right
sry for the mistakw
mistake
there's a silly mistake I found it sry
I corrected it have a look
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