Question

find the sum of the first n positive odd integers​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Sn = 2n²- n

Explaination:-

First odd positive integer (a) = 1

Second odd positive integer (a2) = 3

Third odd positive integer (a3) = 5

Common difference (d) = 2

Hence, A.P :- 1, 3, 5, •••••• 23

Sn = n/2 * [ 2a + ( n - 1 ) d ]

= n/2 * ( 2 + 2n - 2 )/

= n * ( 2n - 1 )

= 2n² - n

Hence, some of first n positive odd integers, Sn = 2n² - n