Question

find the sum of the first n
terms of the arithmatic sequence
1/n, 3/n, 5/n, 7/n ....
​

Answer 1

Answer:

AP is 1 ,3 ,5 ,7 ....

a =1

we have to find D

D= 3 - 1 = 2

Now Apply Sn formula

Sn = n/2 ( 2a + (n-1 ) d )

sn = n/2 (2×1 + (n-1) 2)

Sn = n/2 ( 2 + 2n - 2 )

2 and -2 Will be cancel out

Sn = n/2 (2n)

denominator 2 and multiply 2 will cancel

SO Sn = n^

n^ = n square