Question

Find the sum of the first n terms of the arithmetic sequence:1/n,3/n,5/n........
please solve it......

Answer 1

Answer:

Step-by-step explanation:

put n =1 in equation u wil get first term as a=-1.

your last term is 5-6n.and first term is -1,and total no of term is n.

sum of n term =n/2(first term+last term)

=n/2(a+5-6n)

=n/2(-1+5-6n)

=n(2-3n)

Answer 2

Answer:

$\frac{n + 1}{2}$

Step-by-step explanation:

Sum of first n terms = $\frac{1 + 3 + 5 + 7 + 9 + 11 .....}{n}$ $= \frac{\frac{n(n + 1)}{2} }{n}$ $= \frac{n + 1}{2}$

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