Find the sum of the first one hundred terms of the sequence 5, -6, -17, -28,...
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d= -11
a = 5
n = 100
S(100)= n/2[2a + (n-1)d]
= 100/2[2(5) + 99(-11)]
= 50 ( 10 - 1089 )
= 50 × -1079
= -53,950
a = 5
n = 100
S(100)= n/2[2a + (n-1)d]
= 100/2[2(5) + 99(-11)]
= 50 ( 10 - 1089 )
= 50 × -1079
= -53,950
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