find the sum of the first ten terms of each arithmetic sequence a. a³= 5¹ a⁴=8
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Answer:
a^3 = 5
a^4=8
a^4 - a^3 = a = 8-5 =3
a=3
n=10
sum = n/2*(2a+ (n-1)d)
= 5 (2*3+(9)3)
=5 (6+27)
=5 (33)
=165
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Answered by
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Answer:
165 is the answer........
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