Question

Find the sum of the following :- 1/2xyz, xyz, 3/2 xyz and -2 xyz. ( please give relevant answers stepwise)
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Answer 1

Answer:

The sum of the given monomials is xyz.

Step-by-step-explanation:

We have given some monomials.

We have to find their sum.

The given monomials are

$\displaystyle{\sf\:\dfrac{1}{2}\:xyz\:,\:xyz\:,\:\dfrac{3}{2}\:xyz\:,\:-\:2\:xyz}$

$\displaystyle{\implies\sf\:\dfrac{1}{2}\:xyz\:+\:xyz\:+\:\dfrac{3}{2}\:xyz\:+\:(\:-\:2\:xyz\:)}$

$\displaystyle{\implies\sf\:\left(\:\dfrac{1}{2}\:+\:1\:\right)\:xyz\:+\:\dfrac{3}{2}\:xyz\:-\:2\:xyz}$

$\displaystyle{\implies\sf\:\left(\:\dfrac{1\:+\:2}{2}\:\right)\:xyz\:+\:\left(\:\dfrac{3}{2}\:-\:2\:\right)\:xyz}$

$\displaystyle{\implies\sf\:\dfrac{3}{2}\:xyz\:+\:\left(\:\dfrac{3\:-\:4}{2}\:\right)\:xyz}$

$\displaystyle{\implies\sf\:\dfrac{3}{2}\:xyz\:+\:\left(\:-\:\dfrac{1}{2}\:xyz\:\right)}$

$\displaystyle{\implies\sf\:\dfrac{3}{2}\:xyz\:-\:\dfrac{1}{2}\:xyz}$

$\displaystyle{\implies\sf\:\left(\:\dfrac{3}{2}\:-\:\dfrac{1}{2}\:\right)\:xyz}$

$\displaystyle{\implies\sf\:\left(\:\dfrac{3\:-\:1}{2}\:\right)\:xyz}$

$\displaystyle{\implies\sf\:\cancel{\dfrac{2}{2}}\:xyz}$

$\displaystyle{\implies\sf\:1\:\times\:xyz}$

$\displaystyle{\implies\underline{\boxed{\red{\sf\:xyz\:}}}}$

∴ The sum of the given monomials is xyz.