Question

Find the sum of the following 3,8,13 to 10 Terms Arthamatic progression
​

Answer 1

Answer:

Correct option is

C

1113

Given a=3,l=103,d=5

By using n

th

term a

n

=a+(n−1)d we have,

a

n

=3+(n−1)5

⇒103=3+(n−1)5

⇒103−3=5n−5

⇒105=5n

⇒n=21

S

n

=

2

n

[a

1

+a

n

]

⇒S

n

=

2

21

[3+103]

⇒S

n

=10.5[106]

⇒S

n

=1113