Find the sum of the following
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Answer:
(3x+7y+z)+(x+3z-y) +(x+y)
=(3x+x+x) +(7y-y+y) +(z+3z)
=5x+7y+4z
Answered by
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Answer:
3x+7y+z+x+3z-y+x+y
=3x+x+x+7y-y+y+z+3z
=5x+7y+4z
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