Find the sum of the following.
a) 3a + 4b – 7d, a – 7c + d, 2b – 5c
b) x3+ 7x2y – 11xy2 + 16, -3x3 – 8x2y + 20xy2+ 4
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Answer:
3a+4b+7c,−5a+3b−6c and 4a−2b−4c
The sum of 3a+4b+7c,−5a+3b−6c and 4a−2b−4c is calculated as shown below
(3a+4b+7c)+(−5a+3b−6c)+(4a−2b−4c)
=3a+4a−5a+4b+3b−2b+7c−6c−4c
We get,
=2a+5b−3c
Hence, the sum of 3a+4b+7c,−5a+3b−6c and 4a−2b−4c is 3c
Step-by-step explanation:
hope it help
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