find the sum of the following. A.P 1+3+5+.....+119
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AP is 1,3,5,7....199
a=1d=2 and last term l=199
tn =a+(n−1)d
⇒199=1+(n−1)×2
⇒(n−1) 2 =198
⇒(n−1)=99n=100
∴sum= 2n [a+l]= 2100
[1+199]= 2100 ×200=10000
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