Find the sum of the following A.P.s:
(i) 2, 7, 12, ... to 12 terms
Answers
Answered by
3
Answer:
In the APa=2 d=5
Tn =a+(n-1)d
Tn=2+(12-1)5
=2+55
T 12=57
Answered by
1
a=2 , d=7-2=5. Sum = n/2[2a+(n-1)d]
=12/2[2.2+(12-1)5]
=6[4+55]
=6[59]
=354
=12/2[2.2+(12-1)5]
=6[4+55]
=6[59]
=354
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