Find the sum of the following AP -37,-33,-29,...,to 12 terms
Answers
Answered by
2
Hey mate!
It is give that,
a=-37;d=4;n=12
Now, we know that,
Sn = n/2 {2a+(n-1)d}
So,
S12 = 12/2{2(-37)+(12-1)4}
=>6(-74+44)
=>6(-30)
=>-180.
That's the answer!
Hope it helps :)
Please mark me the brainliest.
It is give that,
a=-37;d=4;n=12
Now, we know that,
Sn = n/2 {2a+(n-1)d}
So,
S12 = 12/2{2(-37)+(12-1)4}
=>6(-74+44)
=>6(-30)
=>-180.
That's the answer!
Hope it helps :)
Please mark me the brainliest.
Answered by
0
Answer:
-180
Step-by-step explanation:
Sn = n/2 [2a+( n-1) d]
Sn = 12/2 [ 2× (-37) + 11× 4]
Sn = 6[-74 + 44]
=> 6[-30]
=> -180
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