Find the sum of the following ap are 2,712, to 10 term
Answers
Answered by
0
Formula-Sn=n/2(2a+(n-1)d
a=2
d=710
n=10
Sn=10/2(2×2+(10-1)710
Sn=5(4+9×710)
Sn=5(4+6390)
Sn=5(6394)
Sn=31970
a=2
d=710
n=10
Sn=10/2(2×2+(10-1)710
Sn=5(4+9×710)
Sn=5(4+6390)
Sn=5(6394)
Sn=31970
Answered by
0
Answer:
Step-by-s(I) 2,7,12........ up to 10 terms
a=2,d=7−2=5
S
n
=
2
n
[2a+(n−1)d]
=
2
10
[2(2)+(10−1)5]
=5[4+9×5]
=5×49
=245
Step explanation:
Hope it is use full to to you.....
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