Question

find the sum of the following APs:
2,7,12,...,to 10term​

Answer 1

Answer:

A=2

D=5

N=10

Sn=n/2[2a+(N-1)d]

= 10/2[2(2)+9(5)]

=5[4+45]

=5×49

= 245

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Answer 2

Answer:

An A.P is 2,7,12,...to10 terms

find : sum of A.P.=Sń=?

for Sń ,a=2,d=5and ń=10

Sń=ń/2[2a+(n-1)d]

=10/2[2×2+(10-1)5]

=5[4+45]

=5×49

=245

Sum of following A.P.is 245