Find the sum of the following APs:
(i) 2,7,12,..., to 10 terms.
(iii) 0.6, 1.7, 2.8,.... to 100 terms.
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Answer:
here is ur answer.
Step-by-step explanation:
in (i) values are
a=7 , d= 5,. n=10
sum =n/2{2a+(n-1)d}
sum = 10/2{2×7+(10-1)5}
sum=295
in (ii) values are
a=0.6 , d=1.1 , n=100
sum =n/2{2a+(n-1)d}
sum=100/2{2×0.6+99×1.1}
sum=5505
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