Question

Find the sum of the following arithmetic Progressions (−)/(+y), (3−2)/(+), (5−3)/(+), … ​

Answer 1

Answer:

sum of n terms =n/2(2a+(n−1)d)

here a=x−y/x=y

d=(3x−2y/x+y)−(x−y/x+y)

=2x−y/x+y

hence sum=

2(x+y)

n

{n(2x−y)−y}

Answer 2

Answer:

Step-by-step explanation:

sum of n terms =n/2(2a+(n−1)d)

here a=x−y/x=y

d=(3x−2y/x+y)−(x−y/x+y)

=2x−y/x+y

hence sum=

2(x+y)

n

{n(2x−y)−y}