Find the sum of the following :
plzz solve this ..
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Answered by
2
as from pic we get
a=(1-1/n)
d=-1/n
Sum of n terms=n/2(2a+(n-1)d)
=n/2(2(1-1/n)+(n-1)-1/n)
=n/2(2-2/n-1+1/n)
=n/2(1-1/n)
=n/2(n-1)n
n get cancelled=(n-1)/2
:) Hope this ans would help u...
a=(1-1/n)
d=-1/n
Sum of n terms=n/2(2a+(n-1)d)
=n/2(2(1-1/n)+(n-1)-1/n)
=n/2(2-2/n-1+1/n)
=n/2(1-1/n)
=n/2(n-1)n
n get cancelled=(n-1)/2
:) Hope this ans would help u...
Answered by
4
Required answer is (n-1)/2.
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