Question

find the sum of the following series 1+square3+3+...upto 8 terms ​

Answer 1

Answer:

1+√3+3.................

common ratio=a2/a1=√3/1

common ratio=√3

sum of n terms=Sn={a(1-r^n)}/(1-r)

Here,

a=1 , r=√3 and n=10

Now we have,

S10={1(1-√3^10)}/(1-√3)

S10={1-243}/(1-√3)

S10={-242(1+√3)}/(1-√3)(1+√3)

S10={-242(1+√3)}/(-2)

S10=121(1+√3)

Hence sum of 10 terms of given G.P series=121(1+√3).

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Answer 2

Answer:

Answer:

1+√3+3.................

common ratio=a2/a1=√3/1

common ratio=√3

sum of n terms=Sn={a(1-r^n)}/(1-r)

Here,

a=1 , r=√3 and n=10

Now we have,

S10={1(1-√3^10)}/(1-√3)

S10={1-243}/(1-√3)

S10={-242(1+√3)}/(1-√3)(1+√3)

S10={-242(1+√3)}/(-2)

S10=121(1+√3)

Hence sum of 10 terms of given G.P series=121(1+√3).

Explanation:

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please mark it as brainiest

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