find the sum of the following series
7+14+21.......+490
Answers
Answered by
20
7+14+21+.....+490
a=7, d=7, l=490
number of terms, n=l-a/d+1
n=490-7/7+1
n=483/7+1
n=69+1=70
sum of these terms is given by
s=n/2 [2a+(n-1)d]
s=70/2 [2×7 (70-1)7]
s=35 [14+(69×7)]
s=35 [14+483]
s=35×497
s=17395
a=7, d=7, l=490
number of terms, n=l-a/d+1
n=490-7/7+1
n=483/7+1
n=69+1=70
sum of these terms is given by
s=n/2 [2a+(n-1)d]
s=70/2 [2×7 (70-1)7]
s=35 [14+(69×7)]
s=35 [14+483]
s=35×497
s=17395
Answered by
0
Answer:
find the sum of 1/7 490and1/5 460
Similar questions