Question

find the sum of the following series to n terms :3.8+6.11+9.14+...

Answer 1

Heya User,

--> 6.11 - 3.08 = 3.03
--> 9.14 - 6.11 = 3.03

Hence, we've found ourselves an A.P. √√ [ Our first step.. ]

Now, identify the components of A.P. -->

--> 1st Term = T(1) = 3.08

--> Common difference = d = 3.03

--> Hence, sum of the series till nth term -->

--> $\frac{n}{2} [ 2(3.08) + ( n - 1 )( 3.03 ) ] \\ \\ = \frac{n}{2} [ 3.03n + 3.13 ]$

--> And hey ^_^ there we have the sum.

--> Plz tell me if that helped ..