Question

Find the sum of the given arithmetic sequences.
2. 3,6,9, ... find 518.​

Answer 1

Answer:

given S60 is equals to 120 sum of first 14 terms for 2518 SN is equal to 2 and 2 and Plus and minus one ds16 is equals to 261 2 April 16 - 1D

Answer 2

Answer:

AP of sequence is

a=3

d=3

no of term unavailable so $a_{n}$=(a+(n-1)d)=518

3+(n-1)=$\frac{518}{3}$→$\frac{518}{3}-3+1$   LCM

$a_{n} =170$

SO NO OF term is 170

$\frac{n}{2}(a+l)$

$\frac{170}{2}(3+518)$

$sum_(n)$=44285

Explanation:

plz mark me as brainliest