Math, asked by sharmanavnita79, 22 days ago

Find the sum of the given four numbers:--
a) successor of 1989
b) predecessor of 6766
c) Successor of successor of 2458
d) predecessor of predecessor of 3002​

Answers

Answered by theleology628
2

Answer:

Successor of 1989 is 1990

Predecessor of 6766 is 6767

Successor of 2458 is 2459

Predecessor of predecessor of 3002 is 3000

Therefore sum of all numbers is

1990

+6767

+2459

+3000

______

14216

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