Math, asked by vivansagarvishnu1000, 11 months ago


Find the sum of the integers between 1 and 200 which are multiples of 3 and 7​

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Answered by rajeshrai180
1

Answer:

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Find the sum of integers between 1 and 200 which are multiples of 3 and 7

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dhanshreporl

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20100is your answer

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vyshnavireddy

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Multiples of 3 are 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 75, 78, 81, 84, 87, 90, 93, 96, 99, 102, 105, 108, 111, 114, 117, 120, 123, 126, 129, 132, 135, 138, 141, 144, 147, 150, 153, 156, 159, 162, 165, 168, 171, 174, 177, 180, 183, 186, 189, 192, 195, 198,

multiples of 7 are 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84, 91, 98, 105, 112, 119, 126, 133, 140, 147, 154, 161, 168, 175, 182, 189, 196

multiples of both 3 and 7 are 21,42,63,84,105,126,147,168,189

then the sum of 21,42,63,84,105,126,147,168,189 is 947

Answered by vanshbhati4820
2

Answer:

we use = n/2 [ a+l]

Step-by-step explanation:

first we find how many number divide by 3 and 7 , between 1 and 200

series = 21 , 42 , 63 ................, 196.

a+(n- 1) ×d = 200

21+21n- 21=200

= 21n =200

n = 9.5

but don't use number in pint so n= 10

n/ 2 [a+l]

= 10 /2 [ 21+196]

= 5× 217

=1,085

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