Find the sum of the integers between 1 and 200 which are multiples of 3 and 7
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Find the sum of integers between 1 and 200 which are multiples of 3 and 7
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dhanshreporl
dhanshreporl Expert
20100is your answer
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vyshnavireddy
vyshnavireddy Genius
Multiples of 3 are 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 75, 78, 81, 84, 87, 90, 93, 96, 99, 102, 105, 108, 111, 114, 117, 120, 123, 126, 129, 132, 135, 138, 141, 144, 147, 150, 153, 156, 159, 162, 165, 168, 171, 174, 177, 180, 183, 186, 189, 192, 195, 198,
multiples of 7 are 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84, 91, 98, 105, 112, 119, 126, 133, 140, 147, 154, 161, 168, 175, 182, 189, 196
multiples of both 3 and 7 are 21,42,63,84,105,126,147,168,189
then the sum of 21,42,63,84,105,126,147,168,189 is 947
Answer:
we use = n/2 [ a+l]
Step-by-step explanation:
first we find how many number divide by 3 and 7 , between 1 and 200
series = 21 , 42 , 63 ................, 196.
a+(n- 1) ×d = 200
21+21n- 21=200
= 21n =200
n = 9.5
but don't use number in pint so n= 10
n/ 2 [a+l]
= 10 /2 [ 21+196]
= 5× 217
=1,085
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