Find the sum of the integers between 1 to 201 which are multiple of 4
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Hey dear here is your answer!!!!
a=4
d=4
An=200
To find the no. of terms :-
An = a+(n-1)d
200=4+(n-1)4
196/4=n-1
49=n-1
n=50
To find their sum :-
Sn = n/2(a+l)
Sn =25(4+200)
Sn=25*204
Sn=5100
Hope it helps u !!!!☺️☺️
a=4
d=4
An=200
To find the no. of terms :-
An = a+(n-1)d
200=4+(n-1)4
196/4=n-1
49=n-1
n=50
To find their sum :-
Sn = n/2(a+l)
Sn =25(4+200)
Sn=25*204
Sn=5100
Hope it helps u !!!!☺️☺️
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