Question

find the sum of the interior angle of a polygon of
1) 6 sides
2) if it is regular polygons find its interior angles​

Answer 1

Our experts are building a solution for this

Answer 2

Answer:

Solution:

(i) 9 sides

No of sides = n = 9

Sum of interior angles of polygon = (2n-4) x 90

= (2 x 9 - 4) x 90

= 14 x 90 = 1260

(ii) 13 sides

No of sides = n = 13

Sum of interior angles of polygon = (2n-4) x 90

= (2 x 13 - 4) x 90

= 1260

(iii) 16 sides

No of sides = n = 16

Sum of interior angles of polygon = (2n-4) x 90

= (2 x 16 - 4) x 90

= 28 x 90 = 2520