Question

find the sum of the length of base of a Trapezium whose altitude is 11 cm and whose area is 0.55 square ​

Answer 1

Answer:

solution

Height =11cm,Area=0.55meter square

change to meter

11/100=0.11m

Area of trapezium=1/2×(a+b)×h

0.55=1/2×(a+b)×0.11

(a+b)=+0.55×2)/0.11

(a+b)=10cm

sum of parallel sides =10cm

Answer 2

answer:- 1000 cm or 10m

step by step explanation:-

are of trapezium=1/2×(a+b)×h

now here , 1/2×(a+b)×h=0.55m^2

we have to find ab here

so first we have to convert 0.55m^2 into cm^2

now we know that 1m=100 , so 1m^2=100×100

so 0.55×100×100=5500

now 1/2 we will transpose to that side so, 5500×2=ab×h(11cm)

now, 11000/11=ab

1000cm=ab

10m=ab