Question

Find the sum of the length of the bases of a trapezium whose altitude is 11 cm and whose area is 0.55 m2 (metre square) ????

Answer 1

Solution :

Height = h = 11 cm = 11 / 100 = 0.11 m; Area = 0.55 m2

Area = ½ x (a +b) x h

0.55 = ½ x (a + b) x 0.11

(a + b) =( 0.55 x 2) / 0.11

( a + b) = 10 cm

∴ Sum of parallel sides = 10 cm.

Answer 2

The sum of the length of the bases of the trapezium is 10cm

Given : The altitude of the trapezium is 11cm and area of the trapezium is 0.55 m².

To find : The sum of the length of the bases of the trapezium.

Solution :

We can simply solve this mathematical problem by using the following mathematical process. (our goal is to calculate the sum of the length of the bases of the trapezium)

Here, we will be using the mathematical formula to calculate the area of a trapezium. Which is :

Area of a trapezium = ½ × (sum of length of two bases) × altitude

Altitude of the trapezium = 11cm = 0.11 m

(As, 1 m = 100 cm, and unit conversion is performed because the area is given in m² unit)

By, putting the given values, in the above mentioned mathematical formula, we get :

0.55 = ½ × (sum of length of two bases) × 0.11

Sum of length of two bases = 0.55 × (1/0.11) × 2

Sum of length of two bases = 10 cm

(This will be considered as the final result.)

Hence, sum of the length of the bases of the trapezium is 10 cm