find the sum of the lengths of the bases of a trapezium whose altitude is 9cm and whose area is 0.72m square.
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Answer:
0.16
Step-by-step explanation:
area of trapezium =h(a+b)/2
0.72=9(a+b)/2
1.44=9(a+b)
a+b=1.44/9
a+b=0.16
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