Question

find the sum of the lengths of the bases of a trapezium whose height is 11cm and area is 0.55cm²​

Answer 1

Answer:

Solution :

Height = h = 11 cm = 11 / 100 = 0.11 m; Area = 0.55 m2

Area = ½ x (a +b) x h

0.55 = ½ x (a + b) x 0.11

(a + b) =( 0.55 x 2) / 0.11

( a + b) = 10 cm

∴ Sum of parallel sides = 10 cm.

Step-by-step explanation:

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Answer 2

Answer:

ans=0.1

Step-by-step explanation:

Ar. of trap.=1/2+(sum of || side)×h

0.55=1/2+(sum of || side)×11

1.1=(sum of || side)×11

sum of || side =0.1 cm.

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