Question

find the sum of the lengths of the bases of a trapezium whose altitude is 17cm and whose area is 0.87 metere square.

Answer 1

Answer:

Step-by-step explanation:

Given : ABCD is a trapezium whose altitude is 17 cm and area 0.87 m².

To Find: (AD + BC)

Solution :

Area of trapezium = $\bold{\dfrac{1}{2}(AD\: + \: BC)\times AE}$

8700 = $\bold{\dfrac{1}{2}(AD\: + \: BC)\times 17}$

(AD + BC) = $\dfrac{8700\times 2}{17}$

(AD + BC) = 1023.52 cm

Sum of parallel side is 1023.52 cm

Hence Solved