find the sum of the lengths of the basis of trapezium whose altitude is 17 cm and whose area is 0.85 m square
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Answer:
So (a+b)= 10
Step-by-step explanation:Area of a trapezium is given by
A=0.5 x (sum of parallel sides) x height
Considering the sides to be 'a' and 'b' respectively the formula thus becomes
A=0.5 x (a+b) x height
Substituting values further
0.85=0.5 x (a+b) x 0.17
Converting them to fractions would save time hence
(85/100)=(5/10) x (a+b) x (17/100)
Which further reduces to
170= 17 (a+b)
So (a+b)= 10
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