find the sum of the measures of the angles of a polygon of 10 side
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Answered by
1
Answer:
sum of measures of interior angles of a polygon = (n - 2) x 180°
where n = no. of sides
(10 - 2) x 180°
= 8 x 180°
= 1440°
sum of exterior angles of polygon of any no. of sides = 360°
Hope it helps...
Answered by
0
Answer:
each angle measure 144° and they all add up to 1,440°
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