Find the sum of the n terms in the A.P.:√2,2√2,3√2
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Given, First term (a) = √2
Common difference (d) = 2√2 - √2
= √2
Sum of first n terms,
(Sn) = n/2 [ 2a + ( n - 1 ) d ]
Sn = n/2 ( 2 * 1 + √2n - √2 )
Sn = n ( 2√2n + 4 - 2√2 )
Sn = 2√2n² + 4 - 2√2n
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